ML20101M544

Combination of Mut Pressure & Level Errors

ML20101M544
Person / Time
Site:	Crystal River
Issue date:	01/17/1996
From:	Harrison D MPR ASSOCIATES, INC.
To:
Shared Package
ML20101M505	List: 3F0496-02, Provides Answers to Questions Received in NRC 960111 RAI & Responses to Addl Questions & Request for Documents Received at 960208 Meeting Re Calculation Which Forms Basis for Mut Pressure/Level Limit Curve in Operating Procedure OP-103B ML20101M511 ML20101M520 ML20101M529 ML20101M544 ML20101M552 ML20101M561 ML20101M564 ML20101M572 ML20101M580 ML20101M584 ML20101M589 ML20101M594
References
102075DHH04, 102075DHH04-R00, 102075DHH4, 102075DHH4-R, NUDOCS 9604050436
Download: ML20101M544 (10)

Text

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EVALUATION OF MAKEUP TANK MAXIMUM PRESSURE PURPOSE:

The purpose of this calculation is to evaluate the maximum pressure in the makeup tank as a function of levelin the tank. The expressions are derived in hand calculatiols. (See MPR calculation 102075DHH01, Reference 2.)

CASE COVERED:

This is the nominal reference case with an attemate method of accounting for the effects of instrument errors. This alternate method is detailed in hand calculations. It is a root mean square combination of i:

the pressure and level errors where those errors are weighted by their sensitivity coefficients. It involves evaluation of the derivative of the allowable pressure vs. level at various values of level to obtain the necessary sensitivity coefficients.

I PARAMETERS:

Vapor pressure of water in the makeup tank at 135 F:

Psat := 2.5375 b Psat = 365.4 b 2

2 in ft Density of water in the makeup tank at 135 F:

P m := 61.4628-Density of water in the BWST at 100 F:

p, := 61.9963-l ft Acceleration of gravity: g := 32.17 h 2

sec l

Minimumlevelin the BWST:

Lmin := 5.0 ft l

Minimum elevation of the surface in the BWST:

E, := Lmin + 119.67 ft E, = 124.67 ft Minimum margin between the top of the pipe at the tie-in and i

Xm := 2 h and the gas in the makeup tank:

Elevation of the top of the 6-in pipe nt the tie-in point:

Ed := 104.5 ft e 3 in Ed = 104.75 ft Minimum elevation of the levelin the pipe from the MUT to the Ex := Ed + Xm Ex = 106.75 ft l

top of the 6-in pipe at the tie-in point:

Mole ratio of Nitrogen to Hydrogen in the MUT cover gas:

y := 0.1 Pipe flow velocity (in the 6-in pipe) at tie-in point:

u e := 6.664 - -

see Gage pressure in the BWST:

Psg := -1.0 ft 62.4 b 3

ft Absolute pressure in the BWST:

Ps := 14.7-

+ Psg Ps = 2.054 10' -

m ft Total head loss from the BWST to the tie-in point at the centerline of the 6-in pipe:

AHac := 11.8704 ft Combined Henry's Law and other constants for Hydrogen and Nitrogen, respectively:

DH := 0.01892 DN := 0.01246 The number of calculational steps to reduce the liquid volume in the makeup tank to zero:

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EXPRESSIONS USED:

The expressions below for the maximum pressure in makeup tank are derived in hand calculations:

I vo + (j - 1) 6v + DH-(1 - vo - ) 6v) vo + (j - 1) 6v + DN'( I - VD - l'0V)

RH(j,vo 6v) :=

RN(j,v.6v) :=

vo + j 6v + D H-(1 - vo - j 6v) vo + J 6v + DN'(I - VO - l'0V)-

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i k j k j T(y,vo,k) := j = 1 j=1 l

1+y The maximum pressure in the makeup tank as a function of the initial gas volume fraction, vo, is as j

follows:

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-P m g Ex + p, g E, - (p, - p m) g Ed + P s g-

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Pmo(vo,y,k) := Psat +

1 T(y,vo,k)

The maximum pressure can also be expressed in gage units by subtracting one atmosphere:

I O Pmog(vo.7,k) := Pmo(vo,y,k) - 14.7 psi The gas volume fraction, vo, is related to the measured levelin the makeup tank, in inches, by the following relation:

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vo(xm) := 0.9089 - 0.0068355 in~I x m MAXIMUM ALLOWANCE FOR INSTRUMENT ERRORS The maximum instrument (:cors in the level, et, and in the pressure, o, are 2.7 in and 1.12 psi, respectively; p

One method to account for these errors is to assume that both of these errors occur at the same time. This can be done by offsetting the level and pressure by these full amounts. This is accomplished by calculating the following quantity:

Pmog(vo(x - 2.7 in),y,k) - 1.12 psi m

For a range of values of level:

x,:= 0 in,5 in 100 in The amount of this reduction in the allowable pressure is APm, where, APm(x m) := Pmog(vo(xm),y,k) - (Pmog(vo(x - 2.7 in),y,k) - 1.12 psi) m This can be shown graphically as:

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This can also be expressed in terms of head, where Hm(x m) I*

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0 20 40 60 80 100 COMBINATION OF ERRORS (rms)

As derived in hand calculations, the statistical combination of the errors in the pressure and level, e p. can be m

expressed as follows, where the values of the error in pressure and level are:

p := 1.12 psi o g := 2.7 in a

m,(x m).=o,'.,. 'd emo,(ve(x m).y.uf}

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\\,m 1

This can be evaluated for a range of levels to obtain the following:

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20 40 60 80 100 The two methods of accounting for instrument errors can be compared by graphing them against the 0

allowable pressure curve that has no allowance for instrument errors.

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Pagef 320 King Street, Alexandria, VA 22314 Calc 102075DHH04 Preparer-

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